Is the number of total atoms on the left side of a balanced equation always equal to the number of total atoms on the right side of the equation? What is the same on the left and right side of a balanced equation? Explain your answer.

Balancing Chemical Equations
Load the simulation Balancing Chemical Equations http://phet.colorado.edu/en/simulation/balancing-chemical-equations

Critical Thinking Questions

Explore the Balancing Chemical Equations simulation.
What are the different ways that the simulation indicates when an equation is balanced?
For each balanced reaction, indicate the total number of molecules in the table below.

Reaction
Total Number of Molecules

Reactant Side (Left)
Product Side (Right)
Make Ammonia

Separate Water

Combust Methane

Is the number of total molecules on the left side of a balanced equation always equal to the number of total molecules on the right side of the equation? Explain your answer.
For each balanced reaction, indicate the total number of atoms in the table below.

Reaction
Total Number of Atoms

Reactant Side (Left)
Product Side (Right)
Make Ammonia

Separate Water

Combust Methane

Is the number of total atoms on the left side of a balanced equation always equal to the number of total atoms on the right side of the equation?
What is the same on the left and right side of a balanced equation? Explain your answer.
Play level 1 of the balancing equation game. Write down the strategies you used to balance chemical equations.
Start level 2 of the balancing equation game using your strategies from Level 1, and adding new strategies as needed.

In the simulation, were you able to use noninteger numbers (like ½ or 0.43) for the coefficients in a balanced equation? Why do you think this is?

Which of the following are coefficients you could use in a balanced equation?
☐ ½ ☐ ¾ ☐ 1 ☐ 2 ☐ 6 ☐ 9

If you were balancing an equation containing the O2 molecule, which of the following would be correct representations of O2 and its coefficient?
☐ ½O2 ☐ O2 ☐ 3O2 ☐ 6O2 ☐ 3O ☐ 5O3

What do you have to do to the coefficients of equation I below to get to equation II?
2 SnO2 + 4 H2 🡪 2 Sn + 4 H2O
SnO2 + 2 H2 🡪 Sn + 2 H2O

 

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